ESysBMWCodingv324364bit [PORTABLE]

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ESysBMWCodingv324364bit [PORTABLE]



 
 
 
 
 
 
 

ESysBMWCodingv324364bit

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I don’t know how to solve this, but when I look at
library oracle substr(table name, 1, 2)

the path of the code is just short of the actual syntax of the table name which is
–(database name)_–(schema name)–(tabel name)

Eg; for
1.
select substr(table name, 1, 2) from dual

The path returned is
1_

instead of
1

I was try to decode the first two character using
substring(table name, 1, 2, 1)

But it return the first character only which is
1

A:

Because your table name has spaces in it, you’ll need to quote it:
select substr(
‘MYTABLE’
, 1
, 2
, 1
) from dual

or use the REPLACE function:
select substr(replaces(‘MYTABLE’,”, ‘_’), 1, 2)

Also, if the name contains column names, you might need to be careful about the casing:
select substr(
replace(
‘MYTABLE’
, ‘MYTABLE’
,”
)
, ‘MYTABLE’
, 1
, 2
50b96ab0b6

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ESysBMWCoding

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